Anybody good at maths??

[downgirl]

Ok it is chemistry based but it is analytical so I'm hoping someone who is good at maths can help me out...I have a sample answer for it but I don't know where the figures are coming from...

This is the question:
1g of a sample of iron ore was dissolved in H2SO4 in a titration vessel yielding Fe2+. This solution was titrated using 0.1M KMnO4.

The analysis was repeated five times with the following titration volumes:
5.0, 4.8, 5.1, 5.2 and 5.3ml.

Calculate the average iron ore content in the ore as a mass percentage.

Aw(Fe) = 55.84 gmol-1


Then basically it works out as
MnO4- : Fe2+
1:5

then it has written down
5n (MnO4-) = n Fe2+

Ans x(%)Fe = 2.794 ml V  KMnO4


How do you work out the 2.794 part??

[fred the red]

ask your lecturer for help!

[illdecide]

ask your lecturer for help!

And stop showing off

[downgirl]

He isn't replying to emails and I'm not in Cork!!!!!!!!!!

f**k off illdecide how is it showing off when I can't do the bloody thing

[milltown row]

will get ya the answer after 6, my wife is not home till then

[thebigfella]

Ok it is chemistry based but it is analytical so I'm hoping someone who is good at maths can help me out...I have a sample answer for it but I don't know where the figures are coming from...

This is the question:
1g of a sample of iron ore was dissolved in H2SO4 in a titration vessel yielding Fe2+. This solution was titrated using 0.1M KMnO4.

The analysis was repeated five times with the following titration volumes:
5.0, 4.8, 5.1, 5.2 and 5.3ml.

Calculate the average iron ore content in the ore as a mass percentage.

Aw(Fe) = 55.84 gmol-1


Then basically it works out as
MnO4- : Fe2+
1:5

then it has written down
5n (MnO4-) = n Fe2+

Ans x(%)Fe = 2.794 ml V  KMnO4


How do you work out the 2.794 part??

I generally find a calculator is good at Maths, ask one of those.

[downgirl]

Ok it is chemistry based but it is analytical so I'm hoping someone who is good at maths can help me out...I have a sample answer for it but I don't know where the figures are coming from...

This is the question:
1g of a sample of iron ore was dissolved in H2SO4 in a titration vessel yielding Fe2+. This solution was titrated using 0.1M KMnO4.

The analysis was repeated five times with the following titration volumes:
5.0, 4.8, 5.1, 5.2 and 5.3ml.

Calculate the average iron ore content in the ore as a mass percentage.

Aw(Fe) = 55.84 gmol-1


Then basically it works out as
MnO4- : Fe2+
1:5

then it has written down
5n (MnO4-) = n Fe2+

Ans x(%)Fe = 2.794 ml V  KMnO4


How do you work out the 2.794 part??

I generally find a calculator is good at Maths, ask one of those.

Oh silly me...

you think I haven't been putting those numbers into the calculator to try and get that number??!!!!!!!!!!!!!!!!!!!!!

[tyrone girl]

Sweet feck how the hell wud any of us know that, more to the point why wud any of us want to know the answer to that

[Tony Baloney]

Ok it is chemistry based but it is analytical so I'm hoping someone who is good at maths can help me out...I have a sample answer for it but I don't know where the figures are coming from...

This is the question:
1g of a sample of iron ore was dissolved in H2SO4 in a titration vessel yielding Fe2+. This solution was titrated using 0.1M KMnO4.

The analysis was repeated five times with the following titration volumes:
5.0, 4.8, 5.1, 5.2 and 5.3ml.

Calculate the average iron ore content in the ore as a mass percentage.

Aw(Fe) = 55.84 gmol-1


Then basically it works out as
MnO4- : Fe2+
1:5

then it has written down
5n (MnO4-) = n Fe2+

Ans x(%)Fe = 2.794 ml V  KMnO4


How do you work out the 2.794 part??

I'm sure someone will take up the challenge but failing that I'll get you an answer tomorrow as I have about 40 analytical chemists at my disposal!

[corn02]

Ok it is chemistry based but it is analytical so I'm hoping someone who is good at maths can help me out...I have a sample answer for it but I don't know where the figures are coming from...

This is the question:
1g of a sample of iron ore was dissolved in H2SO4 in a titration vessel yielding Fe2+. This solution was titrated using 0.1M KMnO4.

The analysis was repeated five times with the following titration volumes:
5.0, 4.8, 5.1, 5.2 and 5.3ml.

Calculate the average iron ore content in the ore as a mass percentage.

Aw(Fe) = 55.84 gmol-1


Then basically it works out as
MnO4- : Fe2+
1:5

then it has written down
5n (MnO4-) = n Fe2+

Ans x(%)Fe = 2.794 ml V  KMnO4


How do you work out the 2.794 part??

Our calculations show that the bird is greater than or equal to the word.

[downgirl]

I'm asking for help how is that showing off

if you don't like it then don't look at it

[tyrone86]

Our calculations show that the bird is greater than or equal to the word.

[anportmorforjfc]

Our calculations show that the bird is greater than or equal to the word.
[/quote]

[ONeill]

Ok it is chemistry based but it is analytical so I'm hoping someone who is good at maths can help me out...I have a sample answer for it but I don't know where the figures are coming from...

This is the question:
1g of a sample of iron ore was dissolved in H2SO4 in a titration vessel yielding Fe2+. This solution was titrated using 0.1M KMnO4.

The analysis was repeated five times with the following titration volumes:
5.0, 4.8, 5.1, 5.2 and 5.3ml.

Calculate the average iron ore content in the ore as a mass percentage.

Aw(Fe) = 55.84 gmol-1


Then basically it works out as
MnO4- : Fe2+
1:5

then it has written down
5n (MnO4-) = n Fe2+

Ans x(%)Fe = 2.794 ml V  KMnO4


How do you work out the 2.794 part??

Fairly straightforward. The low-temperature optical properties of submonolayer CdSe/ZnSe nanostructures have been investigated with nominal layer thickness of 0.15 ML and 0.58 ML CdSe. In photoluminescence excitation spectroscopy (PLE) we observe more than 10 equidistant peaks separated by the ZnSe LO-phonon energy even at energies high above the ZnSe-band edge. The peak heights and line shapes are extremely sensitive to the monolayer coverage, have strongly different intensities in emission and PLE and deviate from the Poissonian intensity distribution expected within the concept of a constant, material specific Huang-Rhys parameter S. A bound polaron model is proposed to explain the optical properties of quantum structures for which the approach of a pure electronic quantum confinement is not appropriate. Intrinsic coherence of joint exciton-phonon modes is very promising, e.g. for application in quantum information processing or coherent population transfer.

[Tony Baloney]

He's a teacher so it must be right